MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        
The velocity of the wind over the surface of the Wing of an aeroplane is 80 ms^-1 and under the wing 60ms^-1 . If the area of the wing is 4m^2 the dynamic lift experienced by the wing is [ density of air =1.3 kg.m^-3 
one month ago

Answers : (1)

Khimraj
2468 Points
							
Dynamic Lift = ½*pA[V22 – V12]
 = ½*1.3*4[802 – 602] = 2.6*(6400-3600) = 2.6*2800 = 7280N
Hope it clears.....................
one month ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 1,590 off

COUPON CODE: SELF10


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 18 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 64 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details