the time period of earth is taken as T and its distance from sum as Rn. what will be the distance of a certain planet from sum whose time period is 64 times than that of earth?

Question

Ashish Kumar · Answer

By keplers law T^2 is directly proportional to R^3. therefore, (R/Rn)^3 = (64 T / T )^2 R = 16 Rn

Pratibha Rani · Answer

same as above

karunya · Answer

T2 is directly proportional to R3 -------1 I taken R0 as an distance from the sun ------2 Divide both2 and 1 T2/64T=R3/R03 R03=64T×R3 R03=(4cube)3Ro3 R0=16

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the time period of earth is taken as T and its distance from sum as Rn. what will be the distance of a certain planet from sum whose time period is 64 times than that of earth?

the time period of earth is taken as T and its distance from sum as Rn. what will be the distance of a certain planet from sum whose time period is 64 times than that of earth?

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the time period of earth is taken as T and its distance from sum as Rn. what will be the distance of a certain planet from sum whose time period is 64 times than that of earth?

the time period of earth is taken as T and its distance from sum as Rn. what will be the distance of a certain planet from sum whose time period is 64 times than that of earth?

3 Answers

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