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Then angle between vector OB and OA will be 90° now break vector OC into its rectangular components..
Like vector OCcos45° along vector OA and OAsin45° along vector OB then add them simple algebraically where |OA|=|OB|=|OC|=R such as
R+Rcos45° along vector OA
(1+1/√2)R
And
R +Rsin45° along vector OB
Now apply formula resultant =(A^2 + B^2 + 2ABcos$)^(1/2) where $ is angle between them
Here $ = 90°
So we have sum =(√2 +1)R
Regards
Arun (askIITians forum expert)
ssuming that all three vectors are in the same plane, We can say that angle between OA and OB is 90°. This implies there resultant i.e. OA + OB = root(R^2 + R^2) => root(2) R.
Now the OC vector and resultant vector are in same direction this we can add them algebrically i.e. R + root(2) R
Answer : R [1+root(2)]
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