- The ratio between orbital and escape velocities is
(A) 1
(B) 2
.(c)√2 (under root)
D)1/√2
- The ratio between orbital and escape velocities is
(A) 1
(B) 2
.(c)√2 (under root)
D)1/√2
Qasim , 7 Years ago
Grade 12th pass
General Physics> The ratio between orbital and escape velo...
3 Answers
Arun
escape velocity is the minimum speed needed for an object to "break free" from the gravitational attraction of a massive body. The escape velocity from Earth is about 40,270 km/h (25,020 mph).The velocity of this orbit depends on the distance from the object to the center of the Earth. The velocityhas to be just right, so that the distance to the center of the Earth is always the same.The orbital velocityformula contains a constant, G, which is called the "universal gravitational constant“.
Hargun singh
I think that is answer is (c) i.e, √2Because the relation between escape velocity and orbital velocity is √2.
adina
Answer:D
Reason:
v(orbital)=under root ( GMe/r)............eq(1)
v(escape)= under root(2GMe/r)...........eq(2)
divide eq(1) by eq (2)
we get, 1/under root (2).
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