0

Guest

Courses New

The ratio between orbital and escape velocities is (A) 1 (B) 2 .(c)√2 (under root) D)1/√2

  1. The ratio between orbital and escape velocities is
    (A) 1
    (B) 2
    .(c)√2 (under root)
    D)1/√2

Grade:12th pass

3 Answers

Arun
25750 Points
6 years ago
escape velocity is the minimum speed needed for an object to "break free" from the gravitational attraction of a massive body. The escape velocity from Earth is about 40,270 km/h (25,020 mph).The velocity of this orbit depends on the distance from the object to the center of the Earth. The velocityhas to be just right, so that the distance to the center of the Earth is always the same.The orbital velocityformula contains a constant, G, which is called the "universal gravitational constant“.
Hargun singh
19 Points
6 years ago
I think that is answer is (c) i.e, √2Because the relation between escape velocity and orbital velocity is √2.
adina
13 Points
3 years ago
Answer:D 
Reason: 
v(orbital)=under root ( GMe/r)............eq(1)
v(escape)= under root(2GMe/r)...........eq(2)
divide eq(1) by eq (2)
we get, 1/under root (2).

Think You Can Provide A Better Answer ?

Other Related Questions on General Physics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More