Grade 12th passGeneral Physics
The radius of the sphere is ( 5.3 +- 0.1 ) cm the percentage error in its volume is ???
The radius of the sphere is ( 5.3 +- 0.1 ) cm the percentage error in its volume is ???
1 Answer
Deepak Kumar Shringi
The volume is given as
V = (4/3)πr3
so,
V = (4/3) x 3.14 x 5.33
thus,
V = 623.30 cm3
now, the error equation
ΔV/V = 3(Δr/r)
or
ΔV = V x 3(Δr/r)
thus,
ΔV = 623.30 x 3x(0.1/5.3)
or error in surface area
ΔV = +/- 35.28 cm3
thus,
ΔV/V x 100 = (35.28/623.30) x 100
so,
ΔV/V x 100 = 5.66 %
V = (4/3)πr3
so,
V = (4/3) x 3.14 x 5.33
thus,
V = 623.30 cm3
now, the error equation
ΔV/V = 3(Δr/r)
or
ΔV = V x 3(Δr/r)
thus,
ΔV = 623.30 x 3x(0.1/5.3)
or error in surface area
ΔV = +/- 35.28 cm3
thus,
ΔV/V x 100 = (35.28/623.30) x 100
so,
ΔV/V x 100 = 5.66 %
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