Given data:
Primary coil turns, Np = 200
Transformation ratio, n = 200
Input voltage, Vp = 220 V
Input power, Pp = 1100 W
Step 1: Find Voltage Across the Secondary Coil
The transformation ratio is given by:
n = Ns / Np = Vs / Vp
Since n = 200, we substitute values:
200 = Vs / 220
Solving for Vs:
Vs = 200 × 220
Vs = 44000 V
Step 2: Find Current in the Secondary Coil
For an ideal transformer, power remains the same in both primary and secondary coils. Therefore,
Pp = Ps
Ps = Vs × Is
1100 = 44000 × Is
Solving for Is:
Is = 1100 / 44000
Is = 0.025 A
Step 3: Find Power in the Secondary Coil
Since the transformer is ideal, there is no power loss, so:
Ps = Pp = 1100 W
Final Answers:
(i) Voltage across the secondary coil, Vs = 44000 V
(ii) Current in the secondary coil, Is = 0.025 A
(iii) Power in the secondary coil, Ps = 1100 W
