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Grade 11General Physics

the position vector of particle changes from 10 m east to 20 m north in one second with respect to a fixed point .the magnitude of average velocity of a particle is
A =10root5 metre per second

Profile image of ayush kapil
8 Years agoGrade 11
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1 Answer

Profile image of Harshit
ApprovedApproved Tutor Answer8 Years ago
Velocity=change in position with respect to timeChange in position =10icap-20jcap and angle between them=90° Magnitude = [(10)^2+(20)^2 - 2*10*20*Cos(90)°]^1/2= 10 root 2Average velocity=10root2/1= 10root2