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Grade: 11

                        

The position of a particle as a function of time is given by x(t)=ln(2t+3) for all positive t , where x is in meters and t is in seconds. What is the particle's acceleration at t=10sec ? A −231​m/s2 B −232​m/s2 C −5294​m/s2 D −234​m/s2 E −51​m/s2

29 days ago

Answers : (1)

ankit singh
askIITians Faculty
596 Points
							

ANSWER

Position of the particle            x(t)=ln(2t+3)  m

Differentiating w.r.t time we get its velocity        v(t)=dtd[x(t)]=2t+32    m/s
 
Differentiating again w.r.t time we get its acceleration        a(t)=dtd[v(t)]=2×(2t+3)22=(2t+3)24    m/s2
   at=10s=(2×10+3)24=5294   m/
29 days ago
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