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the percentage error in measurement of physical quantity,m is given by m=π tanα,is minimum when α is :
m=by differentating on both sidesdm=(πsec2α)dαdividing both sides with m (dm/m)=(sec2α/tanα)dα(dm/m)=(2/sin2α)dαif% error is minimum then sin2α is maximumso α=450PLEASE APROOVE
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