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```
The momentum of a body increases by 20%. What is the % increase it`s K.E ?

```
3 years ago

Ganesh Domale
6 Points
```							KE increases by 400%KE=(p^2)/2m You have given ratios of momentum..Take ratios of initial and final KE emergy and get your answer
```
3 years ago
Hamza
29 Points
```							(mv2-mv1)÷mv1=20/100mv2/mv1=(1/5+1)v1/v2=5/6(Ke1/Ke2)=(v1/v2)^2=25/36(Ke2/ke1-1)=(36/25-1)=11/25Percent=(11/25)×100=44%
```
3 years ago
Hamza
29 Points
```							Plz    verify my   answer  it   is correct u cant disapprove it(mv2-mv1)÷mv1=20/100mv2/mv1=(1/5+1)v1/v2=5/6(Ke1/Ke2)=(v1/v2)^2=25/36(Ke2/ke1-1)=(36/25-1)=11/25Percent=(11/25)×100=44%
```
3 years ago
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