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the magnitudes of two vectors p and q differ by 1 the magnitude of their resultant makes an anglr tan(3/4) with p the angle betwen p and q

navya , 8 Years ago
Grade 11
anser 1 Answers
Riddhish Bhalodia

Last Activity: 8 Years ago

|p| – |q| = 1
(p+q).p = |p+q||p|4/5
|p|2+ |p||q|cos(x) = |p+q||p|4/5
using these equation we square it
put |p| = |q| + 1 from the first equation and then compare the coefficient of the quadratic
and we will get equation in cos(x) which can be solved

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