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The magnitude of the component of the vector 2i+3j+k along 3i+4k isa)1/2b)14/5c)6/5e)2
Unit vector along 3i +4k= (3i +4k)/ 5Now magnitude of vector the component of vector 2i +3j+ k in the direction of 3i +4kTake dot product= (2i +3j +k).(3i +4k)/5= (6 +0 +4)/5= 10/5= 2Hence option E is correct
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