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Grade: 11

                        

The magnitude of displacement and average velocity of the top of the seconds hand of a clock of dial R = 25cm during t = 10s are : ​a) ½ and 1/40 c) ¼ and 1/20 ​b) ¼ and 1/40 d) ½ and 1/30

3 years ago

Answers : (1)

riya
40 Points
							
 
 
 
 
ans b) ¼ and  1/40
GIVEN : radius =  25 cm 
the angle between intial and final point of second  hand is 60 o { 1s = 6 o  then 10 s = 60 o]
WKT  dispacement is straight line distance between initial and final point
hence the triangle  so formed has an angle of 60o . so it is a equilateral triangle
so the displacement = radius= 25 cm = ¼ m
velocity = displacement / time taken = ¼/10 = 1/40 m/s
2 years ago
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