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The height of mercury column in a barometer in a Calcutta laboratory was recorded to be 75 cm .calculate this pressure in SI and CGS using following data : specific gravity of mercury =13.6 , density of water 10^3 kg/m^3 , g=9.8 m/s^2 at Calcutta . Pressure = h(rho)g in usual symbols

milind , 11 Years ago
Grade 12
anser 1 Answers
Arun Kumar

Last Activity: 11 Years ago

Hello Student,
Pressure = \rho *g *h
=>P=0.75*13.6*10^3 * 9.8
This is Pressure in SI units.
Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty
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