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The height from the surface of the earth at which the acceleration due to gravity becomes g/9 where g is theacceleration due to gravity the surface of the earth in terms of radius of earth R is ?

Anshul Gupta , 6 Years ago
Grade 9
anser 1 Answers
Arun

Last Activity: 6 Years ago

Dear Anshul
 
 
By Newton’s law of gravitation, g is inversely proportional to r2,
So, g‘ / g = [R / R+h ] 2
Put g’ = g/9;  h= 2R
 
 
Regards
Arun (askIITians forum expert)

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