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The first ionization potential of Na is 5.1 eV. The value of electron gain enthalpy of Na + will be: (1) – 5.1 eV (3) –10.2 eV (3) + 2.55 eV (4) – 2.55 eV

The first ionization potential of Na is 5.1 eV. The value of electron gain enthalpy of Na + will be: (1) – 5.1 eV (3) –10.2 eV (3) + 2.55 eV (4) – 2.55 eV

Grade:upto college level

1 Answers

Gaurav
askIITians Faculty 164 Points
5 years ago
Ionization energy and electron gain enthalpy of the ion formed are equal in magnitude but opposite to each other. So the correct answer is -5.1 eV

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