The escape velocity from the earth’s surface is 11 km/sec. A certain planet has a radius twice that of the earth but its mean density is the same as that of the earth. The value of the escape velocity from this planet would be(a) 22 km/sec(b) 11 km/sec(c) 5.5 km/sec(d) 16.5 km/sec
saurabh kumar , 11 Years ago
Grade 12
1 Answers
Saurabh Koranglekar
Last Activity: 4 Years ago
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