Grade 11General Physics
- The equation of projectile is y=√3x-gx×x×1÷2 horizontal range is
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- The equation of projectile is y=√3x-gx×x×1÷2 horizontal range is
2 Answers
Arun
Dear Devansh
Please write properly as it is notu derstandable what you have written.You can also attach an image.
Regards
Arun (askIITians forum expert)
Khimraj
the equation of projectile is y = √3x - gx²/2
now,
we know:-
the equation of projectile is : y = xTanФ - gx²/ 2u²Cos²Ф
and the given equation is : y = √3x - gx²/2
on comparing both the equations ,we get
TanФ = √3
so, Ф = 60°
and 2u²Cos²Ф = 2
so u²Cos²Ф = 1
u²cos²60° = 1
u²*(1/2)² = 1
u² = 2²
so, u = 2
Hence, 2 is the initial velocity
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