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Grade 11General Physics

The equation of a projectile are given by y=√3x-(gx^2)/2. The angle of projection with the horizontal is given by.

Profile image of NALIN MAHAJAN
10 Years agoGrade 11
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1 Answer

Profile image of Vikas TU
ApprovedApproved Tutor Answer10 Years ago
Simply compare with the trajectory eqn. of projectile.
y = xtanthetha – gx^2/R where R is range.
plz check i am not sure about – minus eerm.
 
now afetr comparing we get,
tanthetha = root3 
thetha = 60 degree.