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The distance travelled by the freely falling particle during first 3 seconds is equal to that during last second of its fall from the top of a tower. What is the height of the tower The distance travelled by the freely falling particle during first 3 seconds is equal to that during last second of its fall from the top of a tower. What is the height of the tower
S = u*t + (1/2) a* t²S = 0+ 5* 9 = 45 m NowSt = u + (1/2) a(2t-1) = 0 + 5(2t-1) But 45 = 5(2t-1)t = 5 secNowH = ut + (1/2 )*a * t²H = 0 + 5*25H= 125 metres
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