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```
THE DISPLACEMENT OF A PARTICLE STARTING from rest and moving under a constant acceleration is calculated by the formula S= 1/2 at^2 .if there occurs an error of 30% in the measurement of time interval , what error will be introduced in the calculation of S? ANS 69%

```
6 years ago

```							why 69%.if we take 30% less i.e.0.7t then it comes out to be 51%
```
6 years ago
```							that is the reason y i posted this question
```
6 years ago
```							its simple.... error for time is dt/t=30/100=0.3 (here d means delta) that means dt=0.3t  now  S=1/2 at^2 after applying error it becomes..
S+dS =1/2a(t+dt)^2 =1/2a(t^2+2tdt+[dt]^2)  ......  now S=1/2 at^2... hence they get cancelled...  we r left with dS=atdt+a([dt]^2)/2 ... now put dt =0.3t  you would get dS= 0.345at^2...  you want dS/S..  divide the equation by S= 1/2 at^2  .. you would get dS/S= 0.69 =69%
```
6 years ago
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