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`        The breaking stress of steel is 7.9×10^8 N/m^2 and density is 7.9×10^3 kg/m^3.what should be the maximum length of a stellar wire so that it may not break under it`s own weight ?`
2 years ago

Arun
23342 Points
```							Dear Preeti Breaking stress (W/ A) = L * rho * g/27.9 *10^8 = L * 7.9 * 10^3 * 10/22* 10^4 = L  RegardsArun(askIITians forum expert)
```
2 years ago
Preeti
12 Points
```							Breaking stress = L*rho*gL= 7.9*10^8÷7.9*10^3*9.8L=0.102*10^5L=10.2* 10^3L=10.2km So the maximum length of the wire is 10.2km
```
2 years ago
Akanksha gupta
13 Points
```							BS= F/A BS= Mg/A....where Density(D)=M/V                                     V=A×L so... mass= Density×A×L BS= rho*A*L*g/A To find length, L= BS / D*g  L= 7.9× 10^8/ 7.9×10^3×9.8 L= 0.102 × 10^5 L= 10.2km
```
one year ago
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