Grade 12th passGeneral Physics
The angle between the vectors (i^+j^+k^) and (i^-j^-k^) is - sin-1√8/3
- Sin-1(1/3)
- Cos-1√8/3
- Cos-1√(8/3)
The angle between the vectors (i^+j^+k^) and (i^-j^-k^) is
- sin-1√8/3
- Sin-1(1/3)
- Cos-1√8/3
- Cos-1√(8/3)
1 Answer
Harshit Singh
Dear Student
cos x = Dot product of vector A and B/ product of their magnitudes
dot product of A and B= 1-1-1= -1
magnitude of vector A =magnitude of vector B= √3
cos x = (-1)/(√3.√3)
= -1/3
sin^2 x = 1 – cos^2 x
sin x = √8/3
x = sin inverse (√8/3)
Thanks
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