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Grade: 12th pass

                        

The angle between the vectors (i ^+j^+k^) and (i^-j^-k^) is sin-1√8/3 Sin-1(1/3) Cos-1√8/3 Cos-1√(8/3)

one month ago

Answers : (1)

Anand Kumar Pandey
askIITians Faculty
1612 Points
							

Dear Student

cos x = Dot product of vector A and B/ product of their magnitudes
dot product of A and B= 1-1-1= -1
magnitude of vector A =magnitude of vector B= √3

cos x = (-1)/(√3.√3)
= -1/3

sin^2 x = 1 – cos^2 x
sin x = √8/3
x = sin inverse (√8/3)

Thanks
one month ago
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