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The acceleration of a particle is increasing linearly with time t as bt. The particle starts from origin with initial velocity u. The distance travelled by the particle in time t will be: a) ut+(1/3)bt 2 b) ut+(1/2)bt 2 c) ut+(1/6)bt 3 d) ut+(1/3)bt 3 The acceleration of a particle is increasing linearly with time t as bt. The particle starts from origin with initial velocity u. The distance travelled by the particle in time t will be: a) ut+(1/3)bt2 b) ut+(1/2)bt2 c) ut+(1/6)bt3 d) ut+(1/3)bt3
The acceleration of a particle is increasing linearly with time t as bt. The particle starts from origin with initial velocity u. The distance travelled by the particle in time t will be:
a) ut+(1/3)bt2
b) ut+(1/2)bt2
c) ut+(1/6)bt3
d) ut+(1/3)bt3
Displacement is the integral of accelration twice if the relation is gien in time.Therefore,a = bt (given)dv/dt = btdv = bt dtintegerating both sides we get,v = bt^2/2dx = bt^2/2 dtx = bt^3/6Total distance = > ut + (1/6)bt^3 m.
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