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Grade: 11

                        

The acceleration of a particle is increasing linearly with time t as bt. The particle starts from origin with initial velocity u. The distance travelled by the particle in time t will be: a) ut+(1/3)bt 2 b) ut+(1/2)bt 2 c) ut+(1/6)bt 3 d) ut+(1/3)bt 3

4 years ago

Answers : (1)

Vikas TU
12278 Points
							
Displacement is the integral of accelration twice if the relation is gien in time.
Therefore,
a = bt (given)
dv/dt = bt
dv = bt dt
integerating both sides we get,
v = bt^2/2
dx = bt^2/2 dt
x = bt^3/6
Total distance = > ut +  (1/6)bt^3 m.
4 years ago
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