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The above question I do not understand. Please give the solution of A force of 30N is inclined at an angle thetha to the horizontal. if its vertical component is 18N find the horizonta component and the value of thetha

The above question I do not understand. Please give the solution of A force of 30N is inclined at an angle thetha to the horizontal. if its vertical component is 18N find the horizonta component and the value of thetha

Grade:11

2 Answers

Pawan
21 Points
6 years ago
Horizontal component 18N=30*cos():cos()=18/30Cos() =3/5:cos()=53degeeNow, Vertical component =Fsin()=30*sin53=30*4/524N.
Pawan
21 Points
6 years ago
Horizontal component 18N=30*cos():cos()=18/30Cos() =3/5:cos()=53degeeNow, Vertical component =Fsin()=30*sin53=30*4/5=24N.

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