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Square of the momentum operator (issue with taking dot product of complex numbers)

rishav kumar , 12 Years ago
Grade 9
anser 1 Answers
Vikas TU
for a momentum operator p = -iħ d/dx if I square the -iħ part I get (+1)ħ2 but I believe the correct value (as in the kinetic energy of the Hamiltonian) is -ħ/2m d2/dx2.
 
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