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Somebody please ans this question with a detailed explanation

Aayushi Masurekar , 8 Years ago
Grade 12
anser 1 Answers
Arun
mV^2 = mV1^2+2mgh 
m cross 
3^2 = V1^2+2*(0.5-0.5cos 60°)*9.806 = V1^2+4.903 
V1 = √9-4.903 = 2.0 m/sec
Regards
Arun (askIITians forum expert)
Last Activity: 8 Years ago
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