0

HETAV PATEL

Grade 11,

Courses New

Ques.44 Ans is option 3 Plzz solve it as soon as possible IMG is attached

Ques.44
Ans is option 3
Plzz solve it as soon as possible
IMG is attached
 

Question Image
Grade:

1 Answers

suhaas neel
22 Points
5 years ago
Hey there 
we know
 (e and E is emissivity power of an object and a black body respectively NOTE – e,a need not be 1)
Similarly a and A are absorptivity constants.
Lets take a specific case when its a black body where e become E ( as epsilon(emissivity)=1=e/E)(alpha=a/A)(epsilon and alpha for black body are 1)
and similarly a=A  ,your option 3 gives a=1 which is false, real value must be a=A ,
the real relation by kirchoff s laws give us –   e/a=E/A (see here that if you exchange E and a you get e/E=a/e
that is epsilon is equal to alpha THIS IS ONLY VIOLATED BY BLACK HOLES)

Think You Can Provide A Better Answer ?

Other Related Questions on General Physics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More