Q) A string of length L is fixed at one end and carries a mass M at the other end. The string makes 2/pi revolution per second around the vertical axis through the fixed end. The tension in the string is?
Yash Badgujar , 7 Years ago
Grade 11
1 Answers
Arun
Last Activity: 7 Years ago
Dear Yash
length of string = L
mass = M
angular speed (w) = 2/ pi revolutions/sec = 2*2 pi / pi = 4 rad/sec
tension (T) = m *v2 / r
= m* r* w2
= M * L * 42
= 16 ML Newton
Regards
Arun (askIITians forum expert)
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