Position of a particle is given by. X= 3t-4(t)^2+t^3X is distance in metres and t is time in secsFind the average velocity of the particle in the time interval from t=2sec to t=4sec.Sir/ma'am I understood the method in my book which said that find displacement by subtracting x(4)-x(2) and then dividing it by 4-2.But I feel it we should also get the answer when we differentiate x w.r.t t and substitute the values and divide by 2.(dx/dt(4)+dx/dt(2))/2.But I am not getting the same answer. Pls explain why I am wrong,Thanks Jai
Position of a particle is given by. X= 3t-4(t)^2+t^3
X is distance in metres and t is time in secs
Find the average velocity of the particle in the time interval from t=2sec to t=4sec.
Sir/ma'am I understood the method in my book which said that find displacement by subtracting x(4)-x(2) and then dividing it by 4-2.
But I feel it we should also get the answer when we differentiate x w.r.t t and substitute the values and divide by 2.
(dx/dt(4)+dx/dt(2))/2.
But I am not getting the same answer. Pls explain why I am wrong,
Thanks
Jai
Jai Mahajan , 11 Years ago
Grade 12
