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Plz see the attachment and solve this... ..plz explain this properly..................


2 years ago

Susmita
425 Points
							lamda=h/palso potential energy=kinetic energyOr,eV=mv2/2find v from here.So,p=mv=root(2meV)Put it in the eq of lamda.Lamda=h/root(2meV)Where h=planck's constantm=mass of electrone=charge of electronSo V=h2/2me.lamda2=150Vif helped please approve.

2 years ago
Khimraj
3007 Points
							as $\lambda = \sqrt{2meV}/h$so V = $\lambda^{2}$h2/2me = 150VHope it clears....................................................................................................

2 years ago
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