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Grade 11General Physics

Please write full solutions of these two questions ........................................................

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Profile image of Shivam Doharey
9 Years agoGrade 11
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1 Answer

Profile image of Zachariah Abraham
ApprovedApproved Tutor Answer9 Years ago
Well, I don’t know how to do the 2nd one, but here’s the answer to the first:
\vec{PQ} + \vec{PR} + \vec{PS} + \vec{PT} + \vec{PU},
Rearranging for our convenience:
\vec{PQ} + \vec{PT} + \vec{PS} + \vec{PU} + \vec{PR}
Now, you may notice that \vec{PQ} and \vec{PT} are two co-initial vectors forming sides of the parallelogram PQTS.
Hence, their resultant is the diagonal, i.e. \vec{PS}.
So now, the expression becomes:
\vec{PS} + \vec{PS} + \vec{PU} + \vec{PR},
which gives,
2\vec{PS} + \vec{PU} + \vec{PR},
Again, note that \vec{PU} and \vec{PR} form two co-initial sides of the parallelogram PRSU.
Hence, their resultant is the diagonal, i.e. \vec{PS}.
Now the expression reduces to
 2\vec{PS} + \vec{PS},
which gives:
 3\vec{PS}.
It's easy to see that \vec{PS} = 2\vec{PO},
Thus, the answer is 6\vec{PO}.