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`        Please................................solve............`
2 years ago

Arun
23330 Points
```							Dear Anuj Speed of the water stream, v = 15 m/sCross-sectional area of the tube, A = 10–2 m2Volume of water coming out from the pipe per second,V = Av = 15 × 10–2 m3/sDensity of water, ρ = 103 kg/m3Mass of water flowing out through the pipe per second = ρ × V = 150 kg/sThe water strikes the wall and does not rebound. Therefore, the force exerted by the water on the wall is given by Newton’s second law of motion as:F = Rate of change of momentum = ∆P / ∆t= mv / t= 150 × 15 = 2250 N  RegardsArun (askIITians forum expert)
```
2 years ago
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