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Grade: 12th pass
        Please................................solve............
9 months ago

Answers : (1)

Arun
13770 Points
							
Dear Anuj
 

Speed of the water stream, v = 15 m/s

Cross-sectional area of the tube, A = 10–2 m2
Volume of water coming out from the pipe per second,
V = Av = 15 × 10–2 m3/s
Density of water, ρ = 103 kg/m3
Mass of water flowing out through the pipe per second = ρ × V = 150 kg/s
The water strikes the wall and does not rebound. Therefore, the force exerted by the water on the wall is given by Newton’s second law of motion as:
F = Rate of change of momentum = ∆P / ∆t
mv / t
= 150 × 15 = 2250 N

 

 

Regards

Arun (askIITians forum expert)

9 months ago
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