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Grade 11General Physics

please solve and EXPLAIN ques 6.66......................

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Profile image of raghav aggarwal
6 Years agoGrade 11
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1 Answer

Profile image of Ayush_Deep
6 Years ago
The correct answer will be option 4. 
To find equivalent focal length first find equivalent power of the lens mirror combination.
Peq = 2*PL + Pm 
PL power of lens = 1/f
Pm power of lens = - 2/R
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