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Grade: 12th pass
        
Part b please. Please show the diagram and give complete conceptual explanation as is the legacy of this website.
7 months ago

Answers : (1)

Arun
23523 Points
							
Let Resultant force on charge Q at corner A due to charges at corner B & C be F1.
F1 = [(√3Q2)/(4πε0a2)].
Resultant force on charge Q at corner A due to charge q at centre O is F2.
 
F2 = [[(3Qq)/(4πε0a2)]
 
The system of charges will be starting if the force acting on each charge is zero. This happens when q is negative & has magnitude such that F1 = F2.
∴ [(√3Q2)/(4πε0a2)] = [(3Qq)/(4πε0a2)]
∴ √3Q = 3q
∴ q = (Q/√3) ------- magnitude
∴ q = – (Q/√3)
7 months ago
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