Guest

P=α/β exp [-αz/K b θ] θ→temperature P→pressure K b →Boltzmann constant Z→distance The dimensions of [α/β] is- Plz explain what is exp and how α/β=P

P=α/β exp [-αz/Kbθ]
θ→temperature    P→pressure
Kb→Boltzmann constant      Z→distance
The dimensions of [α/β] is-

Plz explain what is exp and how α/β=P

 

Grade:11

2 Answers

Nicho priyatham
625 Points
8 years ago
remember that exp(x) is called exponental function and
EXP( x) =e power x=ex =e^x
so the given equation is 
P= (α/β)e^[-αz/Kbθ] 
 
here u need to no 1 thing that is mathamatical functions like sinx, cosx, (all trignometric functions),logx, ex etc dont have dimensions  
 
 so in the equation P= (α/β)e^[-αz/Kbθ]   the term e^[-αz/Kbθ]  is                  diminsionless
 
so dimensions of P=dimensions of [α/β]
 PLZ APPROVE IF useful in case of any doubts drop it in ans box 
Mohammed Tameem Mohiuddin
10 Points
8 years ago
Thankyou for ur answer nicho priyatham.I found it helpful.

Think You Can Provide A Better Answer ?

ASK QUESTION

Get your questions answered by the expert for free