P=b-x^2/at dimension of a and b where p is power x is the distance and t is the time

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Rohan · Answer

P=b-x^2/atClearly tells that dimension of b is L^2 because same dimensions can be added or subtractedML^2T^-3=L^2/a×TOn equating we will get M^-1T^2

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P=b-x^2/at dimension of a and b where p is power x is the distance and t is the time

P=b-x^2/at dimension of a and b where p is power x is the distance and t is the time

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P=b-x^2/at dimension of a and b where p is power x is the distance and t is the time

P=b-x^2/at dimension of a and b where p is power x is the distance and t is the time

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