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Grade 8General Physics

Monochromatic radiation of wavelength 640.2 nm (1nm = 10–9 m) from a neon lamp irradiates photosensitive material made of caesium on tungsten. The stopping voltage is measured to be 0.54 V. The source is replaced by an iron source and its 427.2 nm line irradiates the same photo-cell. Predict the new stopping voltage

Profile image of prasanjeet kumar
12 Years agoGrade 8
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1 Answer

Profile image of mohini
9 Years ago
λ=640.2nmV∘=0.54Vλ=640.2nmV∘=0.54VLet ϕ∘ϕ∘ be work function and vv be frequency of emitted light.So, eV∘=hv−ϕ∘eV∘=hv−ϕ∘⇒ϕ∘=hcλ−eV∘⇒ϕ∘=hcλ−eV∘=6.6×10−34×3×108(640.2×10−9)–1.6×10−19×0.54=6.6×10−34×3×108(640.2×10−9)–1.6×10−19×0.54=3.093×10−19–0.864×10−19=3.093×10−19–0.864×10−19=2.229×10−19J1.6×10−19=2.229×10−19J1.6×10−19=1.39eV=1.39eVλ′=427.2nmλ′=427.2nmLet V′∘V∘′ be new stopping potential.eVo′=hcλ′−ϕ∘eVo′=hcλ′−ϕ∘=6.6×10−34×3×108(427.2×10−9)–2.229×10−19=6.6×10−34×3×108(427.2×10−9)–2.229×10−19=4.63×10−19–2.229×10−19=4.63×10−19–2.229×10−19=2.401×10−19J1.6×10−19=2.401×10−19J1.6×10−19=1.5eV