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`        Length of a minute hand of a clock is 4.5cm.find the average velocity of the tip of minute hand between 6 A.M to 6.30 A.M and 6 A.M to 6.30P.M `
one year ago

## Answers : (4)

```							Between 6 am to 6:30 amAverage speed = Total distance/ Time= πr / (30 × 60 seconds)= 4π/1800= 0.00698 cm/sAverage velocity = Total displacement/ Time= 2r / (30 × 60 seconds)= 9 / 1800= 0.005 cm/s_____________________________Average velocity and average speed between 6 am to 6:30 pm is same as that of 6 am to 6:30 am
```
one year ago
```							 Average speed is given by Total distance divided by Timespeedavg = πr /1800= π*4.5/1800= 0.00785 cm/sAverage velocity will be given by  Total displacement divided by Timevavg = 2r / 1800= 9 / 1800= 0.005 cm/sHope it clears.
```
one year ago
```							Displacement is the shortest route between 2 points therefore here displacement =2r= 2x4.5For 6 am to 6:30 amt=30 min = 30x60                 =1800sTherefore, v= 2x4.5                        1800              =5x10^-3 cm/s For 6 am to 6:30 pmt=12.5hr =12x60x60+30x60               =45000sTherefore, v=2x4.5                       45000                     =2x10^-4 cm/s
```
6 months ago
```							Part 1Vav= displacement ÷ time Vav=(4.5+4.5)÷(30×60)= 1÷200 cm/ s Part 2Vav= displacement ÷timeVav= (4.5+4.5)÷(12hours×60×60 + 30min×60)Vav = 1÷5000 cm / s Vav=
```
3 months ago
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