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Grade 12th passGeneral Physics

in the double slit experiment if one slit have a width as twice as the other what will happens to the interference pattern

moon watcher

7 Years agoGrade 12th pass

1 Answer

Arun

7 Years ago

Maximum amplitude & Intensity -

When $\theta = 0,2\pi ---2n\pi$

- wherein

$A_{max }= A_{1}+A_{2}$

$I_{max }= \left ( \sqrt{I_{1}}+\sqrt{I_{2}} \right )^{2}$

and

Minimum amplitude & Intensity -

$\theta = \left ( 2n+1 \right )\pi$

- wherein

$A_{min }= A_{1}-A_{2}$

$I_{min }= \left ( \sqrt{I_{1}}-\sqrt{I_{2}} \right )^{2}$

In this case, since $A \propto \ width$ of slits

$A_{1} = 2A$

$A_{2} = A$

$A^{max} = A_{1}+A_{2} = 3A$ and $A^{min} = \left ( A_{1} \right-A_{2} ) =A$

Hence amplitude/intensity of both maxima and minima increases

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