In an experiment on photoelectric effect, the slope of the cut-off voltage versus frequency of incident light is found to be 4.12 × 10–15 V s. Calculate the value of Planck’s constant.

Question

Vikas TU · Answer

given, slope of cut-off voltage versus frequency of incident light = 4.12 × 10^-15 V/s we know, slope of graph = Plank's constant/charge on electron or, slope = h/e so, h = slope × e = 4.12 × 10^-15 V/s × 1.6 × 10^-19 C = 6.592 × 10^-34 Js hence, value of planks constant is 6.592 × 10^-34 J.s

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In an experiment on photoelectric effect, the slope of the cut-off voltage versus frequency of incident light is found to be 4.12 × 10–15 V s. Calculate the value of Planck’s constant.

In an experiment on photoelectric effect, the slope of the cut-off voltage versus frequency of incident light is found to be 4.12 × 10–15 V s. Calculate the value of Planck’s constant.

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In an experiment on photoelectric effect, the slope of the cut-off voltage versus frequency of incident light is found to be 4.12 × 10–15 V s. Calculate the value of Planck’s constant.

In an experiment on photoelectric effect, the slope of the cut-off voltage versus frequency of incident light is found to be 4.12 × 10–15 V s. Calculate the value of Planck’s constant.

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