Vikas TU
Last Activity: 4 Years ago
given, slope of cut-off voltage versus frequency of incident light = 4.12 × 10^-15 V/s
we know, slope of graph = Plank's constant/charge on electron
or, slope = h/e
so, h = slope × e
= 4.12 × 10^-15 V/s × 1.6 × 10^-19 C
= 6.592 × 10^-34 Js
hence, value of planks constant is 6.592 × 10^-34 J.s