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in an elevator moving up with an acceleration g the force exerted on the floor by a passenger of mass M is a.Mg b.1/2Mg c.zero d.2Mg

Medical Student , 7 Years ago
Grade 12th pass
anser 2 Answers
Arun

Last Activity: 7 Years ago

If the Elevator is moving up with acceleration g, same will be the acceleration for the Person inside (as we see from the ground).
The person's weight is mg downwards, the only force that is acting on the Person is the force from the lift floor. Let that reaction force be R. This R has to overcome his weight and still accelerate him to g,
We have R - mg = ma (and here 'a' is given as 'g')
therefore, R = 2mg.

Khimraj

Last Activity: 7 Years ago

Draw the free body diagram of paasenger. there will be one downward foce = M*geff.
Here geff = g+g = 2g.
So force exerted on the floor by a passenger will be 2Mg.

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