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IN A PROJECTILE MOTION THE HORIZONTAL DISPLACEMENT IS GIVEN BY X=(ucos theta)t AND THE VERTICAL DISPLACEMENT IS GIVEN BY Y=(usin theta)t.THE ABOVE DISPLACEMENTS ARE DERIVED USING EQUATION OF MOTIONS:s = ut +1/2 at^2=(u cos theta)t-1/2 (0)t^2=(ucos theta)ts=ut + 1/2 at^2=(usin theta)t -1/2gt^2IF I USE V=S/T TO FIND HORIZONTAL AND VERTICAL DISPLACEMENT I GET ONLY THE HORIZONTAL DISPLACEMENT AND NOT THE VERTICAL DISPLACEMENT.V=S/Tu cos theta=x/t(u cos theta)t=xV=S/Tu sin theta=y/t(u sin theta)t=ySEE AM NOT GETTING (usin theta)t-1/2 gt^2PLEASE CLARIFY MY DOUBT!

Navjyot Kalra , 11 Years ago
Grade 10
anser 1 Answers
Saurabh Koranglekar

Last Activity: 4 Years ago

Dear student

The displacement is also a vector quantity

please find the link to understand this topic better

https://www.askiitians.com/iit-jee-physics/mechanics/motion-in-two-dimensions.aspx


Regards

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