IN A PROJECTILE MOTION THE HORIZONTAL DISPLACEMENT IS GIVEN BY X=(ucos theta)t AND THE VERTICAL DISPLACEMENT IS GIVEN BY Y=(usin theta)t.

THE ABOVE DISPLACEMENTS ARE DERIVED USING EQUATION OF MOTIONS:

s = ut +1/2 at^2=(u cos theta)t-1/2 (0)t^2=(ucos theta)t

s=ut + 1/2 at^2=(usin theta)t -1/2gt^2

IF I USE V=S/T TO FIND HORIZONTAL AND VERTICAL DISPLACEMENT I GET ONLY THE HORIZONTAL DISPLACEMENT AND NOT THE VERTICAL DISPLACEMENT.

V=S/T

u cos theta=x/t

(u cos theta)t=x

V=S/T

u sin theta=y/t

(u sin theta)t=y

SEE AM NOT GETTING (usin theta)t-1/2 gt^2

PLEASE CLARIFY MY DOUBT!

Navjyot Kalra , 11 Years ago

Grade 10