IN A PROJECTILE MOTION THE HORIZONTAL DISPLACEMENT IS GIVEN BY X=(ucos theta)t AND THE VERTICAL DISPLACEMENT IS GIVEN BY Y=(usin theta)t.THE ABOVE DISPLACEMENTS ARE DERIVED USING EQUATION OF MOTIONS:s = ut +1/2 at^2=(u cos theta)t-1/2 (0)t^2=(ucos theta)ts=ut + 1/2 at^2=(usin theta)t -1/2gt^2IF I USE V=S/T TO FIND HORIZONTAL AND VERTICAL DISPLACEMENT I GET ONLY THE HORIZONTAL DISPLACEMENT AND NOT THE VERTICAL DISPLACEMENT.V=S/Tu cos theta=x/t(u cos theta)t=xV=S/Tu sin theta=y/t(u sin theta)t=ySEE AM NOT GETTING (usin theta)t-1/2 gt^2PLEASE CLARIFY MY DOUBT!

Navjyot Kalra , 10 Years ago

Grade 10