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in a hydraulic lift, the piston P2 has a diameter of 50 cm and that of P1 is 10 cm. what is the force on P2 when 1 N of force is applied on P1?

ranganathan , 6 Years ago
Grade 11
anser 1 Answers
Shweta gabale

Last Activity: 6 Years ago

Since pressure is the ratio of force and area. So, pressure is 1N / π/4 (0.1)^2 = 127.38 N/mm^2.Hence, force at p2 will be 127.38 ×π/4 × 0.5^2 = 25 N

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