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In a cylinder there are 60gm of neon and 124gm of oxygen.If pressure of mixture of gases is 30bar.then partial pressure of oxygen in bar?
In a cylinder there are 60gm of neon and 124gm of oxygen.If pressure of mixture of gases is 30bar.then partial pressure of oxygen in bar?

```
4 years ago

## Answers : (1)

Vikas TU
14149 Points
```							Pt = Pa + PbPa = Xa*PtPb = (1 – Xa)*PtNow moles of the gaes are:60/20 => 3 molesand124/32 =  4 moles respectively.Mole fraction of Ne gas = > 3/(3 + 4) = 3/7 = XaPutting in Pa and Pb we get,Pa = (3/7) * 30 = 90/7 = > 12.84 bar.Pb = (4/7)*30 = > 120/7 = > 17.14 bar.
```
4 years ago
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