Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        In a car race , car A takes time t less than car B and passes the finishing point with a velocity v more than the velocity with which car B passes the point. Assuming that the cars start fromrest and travel with constant accelerations a1 and a2 show that            v = (a1a2)1/2`
4 years ago

Tarsh
13 Points
```							Let s be the distance travelled by each carvA=2a1s−−−−√vA=2a1sAlso vB=2a2s−−−−√vB=2a2s t1=2sa1−−−√t1=2sa1t2=2sa2−−−√t2=2sa22a1s−−−−√−2a2s−−−−√=v02a1s−2a2s=v0and2sa2−−−√−2sa1−−−√=t02sa2−2sa1=t0v0t0=a1−−√−a2−−√1a2√−1a1√v0t0=a1−a21a2−1a1=a1a2−−−−√
```
one year ago
Think You Can Provide A Better Answer ?

## Other Related Questions on General Physics

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 18 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions