if y=x sin inverse x/under root 1-x^2 then show that dy/dx=sin inverse x/(1-x^2)^3/2

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Dear student Please use brackets as it is not clear where divide sign is used and till where other sign are used. Please attach an image, if possible

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if y=x sin inverse x/under root 1-x^2 then show that dy/dx=sin inverse x/(1-x^2)^3/2

if y=x sin inverse x/under root 1-x^2 then show that dy/dx=sin inverse x/(1-x^2)^3/2

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if y=x sin inverse x/under root 1-x^2 then show that dy/dx=sin inverse x/(1-x^2)^3/2

if y=x sin inverse x/under root 1-x^2 then show that dy/dx=sin inverse x/(1-x^2)^3/2

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