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If the surface area of the cube is changing at a rate of 6m2/s find the rate of change of body diagonal atthe instant when side length is 0.5 m

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2 years ago

Arun
24742 Points
```							 Surface area of cube = 6*a^2 where a is its side.Now given,dS/dt = 6 m/s^2thus,dS/dt = 12*a*da/dt = 6da/dt = 6/12............................(1) Now relan. b/w body diagonal and length is:l = a*root3dl/dt = root3 * da/dt............(2)from eqns. (1) and (2)dl/dt = root3 * 6/12 = > root3/2.
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2 years ago
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