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         									If the length of a simple pendulum is doubled keeping its amplitude constant its energy will be																		a) 						Unchanged												b) 						Doubled																						c) 						Four times												d) 						Halved
4 months ago

## Answers : (3)

Arun
22294 Points
							 As we learnt inTime period of oscillation of simple pendulum -$T=2\pi \sqrt{\frac{l}{g}}$- whereinl = length of pendulum g = acceleration due to gravity.  Halved Hence option D is correct

4 months ago
Sanjeev Narang
36 Points
							Simple pendulum is doing simple harmonic motion . so, Total energy is given by:      T. E. = 1/2*m*A2*(\omega)2 But (\omega)2 =g/lThen, T. E. =1/2*m*A2*g/lAs mass(m), 1/2, Amplitude(A), and Acceleration due to gravity(g) are constant, then:         T. E. is inversely proportional to length of the simple pendulum(l). Therefore if length become doubled T.E. becomes halved.So option (d) is the answer.

4 months ago
Khimraj
3008 Points
							 the answer is (d) halved. we know the formula t = 2pi * root(l/g).so when l’ = 2l. t becomes root(2) times more.

4 months ago
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• Test paper with Video Solution
• Mind Map
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• NCERT Solutions
• Discussion Forum
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