Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Live 1-1 coding classes to unleash the creator in your Child
If the earth , supposed to be a uniform sphere , contracts slightly so that its radius decreases by 1/n times than the present radius , show that the duration of the day decreases by 48/n hours.
Dear student Assume earth radius R moment of inerta of earthI1 = 2/5 MR^2 Now according to questionEarth radius becomes R – R/n MI of the earth of radius(R/n) I2 = 2/5 (R – R/n)^2 There is no external torque on the earth So, Angular momentum would be conserveI1 w1 = I2 w2 you will get T = 24 (1 + 2/n)^-1 T = 24 (1 – 2/n) hence day is shorten by 24 – 24 (1 – 2/n) = 48/n
Now according to question
Earth radius becomes R – R/n
MI of the earth of radius
(R/n)
I2 = 2/5 (R – R/n)^2
There is no external torque on the earth
So, Angular momentum would be conserve
I1 w1 = I2 w2
you will get
T = 24 (1 + 2/n)^-1
T = 24 (1 – 2/n)
hence day is shorten by
24 – 24 (1 – 2/n) = 48/n
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -